Answer:
Option C
Explanation:
Apply conservation of momentum
m1v1 = (m1+m2)v
$v= \frac{m_{1}v_{1}}{(m_{1}+m_{2})}$
Here, v1 = 36 km/hr=10 m/s
m1 =2 kg , m2=3 kg
$v= \frac{10\times2}{5}=4 m/s$
K.E ( initial ) $= \frac{1}{2}\times2\times(10)^{2}=100 J$
K.E (final) $= \frac{1}{2}\times(3+2)\times(4)^{2}=40 J$
Loss in K.E =100-40=60
Althernatively use this formula
$-\triangle E_{k}=\frac{1}{2}\frac{m_{1}m_{2}}{(m_{1}+m_{2})}(u_{1}-u_{2})^{2}$